Effacer les filtres
Effacer les filtres

index no for iterations

1 vue (au cours des 30 derniers jours)
Nitheesh M
Nitheesh M le 25 Avr 2015
Attempted to access x(2,1.01); index must be a positive integer or logical.
Error in ==> latest at 19 dx1=x(2,i);
my code ::
for i = 0:0.01:2 yd(j) = sin(2*pi*i); j=j+1; dx1=x(2,i);
should i be integer values only..if then my yd will always be 0 right..i need values of yd from 0 to 2..and corresponding dx1...
please help me out

Réponse acceptée

Stephen23
Stephen23 le 25 Avr 2015
You probably don't need a loop at all, and can simply vectorize the code anyway:
x = 0:0.01:2;
y = sin(2*pi*x);
and most likely any following value manipulations can also be vectorized. This is much faster and neater than using loops, which as something low-level programming languages rely on but are not a good use of MATLAB.

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by