Effacer les filtres
Effacer les filtres

Discrete time nonlinear system

3 vues (au cours des 30 derniers jours)
dab483
dab483 le 16 Nov 2011
How can i develop this discrete-time nonlinear system in simulink?
[x]=[0.01x1 - x2; x1 - 0.003x2^2]
  1 commentaire
Fangjun Jiang
Fangjun Jiang le 16 Nov 2011
Do you mean?
dx1/dt=0.01*x1-x2;
dx2/dt=x1-0.003*x2^2;

Connectez-vous pour commenter.

Réponse acceptée

Fangjun Jiang
Fangjun Jiang le 16 Nov 2011
Grab an Integrator block, if the input is dx1/dt, then the output is x1. Do the same for x2 and then you have all you need to build the equation. x2^2 is the same as x2*x2.
You don't seem to have any inputs, so set the initial condition of the Integrator blocks to specify the initial value of x1 and x2 and then run the simulation to see the dynamics.
  4 commentaires
dab483
dab483 le 17 Nov 2011
sorry.it is my mistakes. i type it wrongly. it suppose
x1(k+1)=0.01*x1(k)-x2(k);
x2(k+1)=x1(k)-0.003*x2^2(k);
Fangjun Jiang
Fangjun Jiang le 17 Nov 2011
Then replace the Integrator block with the Unit Delay (1/Z) block. The input is x(k+1), the output is x(k).

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur General Applications dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by