Replace the element in the cell array with space inbetween

I have a cell array element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}

I need to replace num riqu = numeric

             con tant = constant

how can I do this ?

[Gopalakrishnan venkatesan]

Is it possible with the regexprep

Answer 1

[Guillaume]

It's not clear how generic of an answer you are looking for. In you particular example, the simplest way would be:

c = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'};
c(strcmp(c, 'num riqu')) = {'numeric'};
c(strcmp(c, 'con tant')) = {'constant'}

[Guillaume]

A more generic way:

c = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'};
replacements = {'num riqu', 'numeric'
                'con tant', 'constant'};  
%column 1 of replacements is word to replace, column 2 is replacement

[toreplace, replacementrow] = ismember(c, replacements(:, 1));
c(toreplace) = replacements(replacementrow, 2)

[Gopalakrishnan venkatesan]

Is it possible with the command regexprep??

[Guillaume]

You would have to use one regexprep per expression you want to replace, so while you could do it, it wouldn't be any simpler.

In any case, as defined in your example, the search patterns don't need regular expressions.

Answer 2

[Azzi Abdelmalek]

element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
element=strrep(element,'num riqu','numeric');
element=strrep(element,'con tant','constant')

[Gopalakrishnan venkatesan]

Is it possible with the command regexprep??

[Azzi Abdelmalek]

element = {'num riqu' ; 'num riqu' ; 'con tant' ; 'con tant'}
element=regexprep(element,'num riqu','numeric')
element=regexprep(element,'con tant','constant')

But strrep is faster then regexprep