Why I am getting error while using qammod function ?

6 vues (au cours des 30 derniers jours)
majdi Khlfalla
majdi Khlfalla le 25 Oct 2024
Hi
I am using matlab R2014a and I using the code below :
%% Simulation Parameters
numBits = 20000;
modOrder = 16;
%% Creat a source signal and apply 16-QAM modulation
srcBits = randi([0 1],numBits,1);
modOut = qammod(srcBits,modOrder,'InputType','Bit','UnitAveragePower',true);
%% Apply AWGN
SNR = 15;
chanOut = awgn(modOut,SNR);
scatterplot(chanOut)
%% Demodulate received signal
demodOut = qamdemod(chanOut,modOrder,'OutputType','Bit','UnitAveragePower',true);
I should have got the figuer above. But I am having the following error instead !
( Note : I run this code while typing my question and got the result above )
Error using qammod (line 28)
Too many input arguments.
and line 28 is found here :
27 - if(nargin>4)
28 - error(message('comm:qammod:numarg2'));
29 - end
thank you
  2 commentaires
Walter Roberson
Walter Roberson le 25 Oct 2024
You should double-check your help documentation.
I suspect that back in R2014a that there was no support for 'UnitAveragePower'
majdi Khlfalla
majdi Khlfalla le 26 Oct 2024
Modifié(e) : majdi Khlfalla le 26 Oct 2024
@Walter Roberson yes, I did some research and found that problem was my matlab version. And instead of averaging power, I have to noramlize it in separate step. Thank you walter for your help

Connectez-vous pour commenter.

Réponse acceptée

Saurabh
Saurabh le 25 Oct 2024
I've encountered a similar issue in the past, and I was able to resolve it by upgrading my MATLAB version to R2016a or later.
I Hope this helps
  1 commentaire
majdi Khlfalla
majdi Khlfalla le 26 Oct 2024
@Saurabh Yeah, the problem was in my matlab version, I should upgrade now. many thanks

Connectez-vous pour commenter.

Plus de réponses (0)

Tags

Produits


Version

R2014a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by