I have a bug on my code

It keeps saying u(t) is not defined even though I did.
% t bounded between -1 and 1 with a step of 0.01
t = -1:0.01:1;
%Plot on a graph
x_1 = 5 * u(t-0.1);
x_2 = 2 * rectangularPulse(t/0.3);
x_3 = 4 * sinc(t/0.2);
figure
plot(t,x1,'g',t,x2fx,'b',t,x3,'c');
Unrecognized function or variable 'x1'.
% Label the graph
xlabel('Amplitude')
ylabel('Time t[s]')
title('Assignment 3')
legend("x1(t)","x2(t)","x3(t)");
grid on;
% Step function implementing 𝑦(𝑡) = 𝑢(𝑡)
function y =u(t)
y(t > 0) = 1;
y(t == 0) = 0.5;
y(t < 0) = 0;
end
% Rectangular pulse function implementing 𝑦(𝑡) = Π(𝑡)
function y = rectangularPulse(t)
y = (t >= -0.5 & t <= 0.5);
end
% Sinc function implementing 𝑦(𝑡) = 𝑠𝑖𝑛𝑐(𝑡)
function y = sinc(t)
y = (sin(pi.*t) / pi.*t);
end

1 commentaire

Stephen23
Stephen23 le 14 Sep 2025
Déplacé(e) : Image Analyst le 14 Sep 2025
You have not defined the following variables/functions: x1, x2fx, x3.
Once you define those variables then your code works:
% t bounded between -1 and 1 with a step of 0.01
t = -1:0.01:1;
%Plot on a graph
x1 = 5 * u(t-0.1); % fixed name
x2 = 2 * rectangularPulse(t/0.3); % fixed name
x3 = 4 * sinc(t/0.2); % fixed name
figure
plot(t,x1,'g',t,x2,'b',t,x3,'c');
% Label the graph
xlabel('Amplitude')
ylabel('Time t[s]')
title('Assignment 3')
legend("x1(t)","x2(t)","x3(t)");
grid on;
% Step function implementing 𝑦(𝑡) = 𝑢(𝑡)
function y = u(t)
y(t > 0) = 1;
y(t == 0) = 0.5;
y(t < 0) = 0;
end
% Rectangular pulse function implementing 𝑦(𝑡) = Π(𝑡)
function y = rectangularPulse(t)
y = (t >= -0.5 & t <= 0.5);
end
% Sinc function implementing 𝑦(𝑡) = 𝑠𝑖𝑛𝑐(𝑡)
function y = sinc(t)
y = (sin(pi.*t) / pi.*t);
end

Connectez-vous pour commenter.

Réponses (1)

Image Analyst
Image Analyst le 14 Sep 2025

0 votes

You have not defined x1. x1 is a differently-named variable than x_1.
  1. If they should be the same variable, then use a consistent name, either with or without the underline.
  2. Otherwise if they are different variables you need to define exactly what x1 is.

Catégories

En savoir plus sur Animation dans Centre d'aide et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by