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finding the index of str's charachter from another vector

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Mohamuud hassan
Mohamuud hassan le 24 Mai 2015
Commenté : Mohamuud hassan le 25 Mai 2015
hello who can help me for correcting this error: str vector contains 57 character and X vector 1560 charaters. i was finding the index of str's charachter from excel data and results become 56 while i was estimating 57 because the size of str vector was 57. so i need help for this problem.
X={'as modeling of changes in backbone conformation still lacks a computationally efficient solution, we developed a discretisation of the conformational states accessible to the protein backbone similar to the successful rotamer approach in side chains. The BriX fragment database, consisting of fragments from 4 to 14 residues long, was realized through identification of recurrent backbone fragments from a non-redundant set of high-resolution protein structures. brix contains an alphabet of more than 1,000 frequently observed conformations per peptide length for 6 different variation levels. analysis of the performance of brix revealed an average structural coverage of protein structures of more than 99 percent within a root mean square distance of 1 angstrom. globally, we are able to reconstruct protein structures with an average accuracy of 0.48 angstrom rmsd. as expected, regular structures are well covered, but, interestingly, many loop regions that appear irregular at first glance are also found to form a recurrent structural motif, albeit with lower frequency of occurrence than regular secondary structures. larger loop regions could be completely reconstructed from smaller recurrent elements, between 4 and 8 residues long. finally, we observed that a significant amount of short sequences tend to display strong structural ambiguity between alpha helix and extended conformations. when the sequence length increases, this so-called sequence plasticity is no longer observed, illustrating the context dependency of polypeptide structures.'};
str='steganography is the art and science of covered or hidden';
for m = 1:numel(X)
Y = bsxfun(@eq,X{m}(:),str);
for n = 2:size(Y,2)
Y(:,n) = Y(:,n) & cumsum(Y(:,n-1))>0;
end
Z = find(any(diff([false(size(str));cumsum(Y)>0],1),2))
end
  5 commentaires
Jan
Jan le 24 Mai 2015
@abdulkarim hassan: If the problem is solved already, please post this as an answer and accept it. Then readers will not waste the time to understand the question anymore. Thanks.
Mohamuud hassan
Mohamuud hassan le 25 Mai 2015
i am sorry Jan Simon, i don't know well how to use this forum.

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