Partial Differentiation of a function

syms x y

f=x^2+2*y^2-22

P=diff(f,x)

Here, I have calculated the (partial) differentiation of function "f" w.r.t 'x'

Now, I want to know the value of 'P' at certain point (say x=1.5, y=2.0)

Please help!

[Jimmy]

The information you share is necessary for me, I've been looking for it for a few days and it helped me get my job done.

Answer 1

[Grzegorz Knor]

One of the possibilities:

syms x y
f=x^2+2*y^2-22
P=diff(f,x)
subs(P,{x,y},{1.5,2})

[manish sharma]

Thanks Grzegorz, that worked.