How can i replace a number with its no of ocurrences

i have a matrix=a=[1 0 1 0 1;0 1 1 1 1;1 1 0 1 1;1 1 1 1 1] i want to replace ones by their no of occurences in each row like a=[1 0 2 0 3;0 1 2 3 4;1 2 0 3 4;1 2 3 4 5]

[Image Analyst]

Is this your homework?

Answer 1

[Mohammad Abouali]

a=[1 0 1 0 1;0 1 1 1 1;1 1 0 1 1;1 1 1 1 1];
cumsum(a,2).*a
ans =
     1     0     2     0     3
     0     1     2     3     4
     1     2     0     3     4
     1     2     3     4     5

[Ayesha Maroof]

thanx alot Mohammad Abouali.i lilttle more help needed.can i shuffle the values now.that zeros remain and its place but rest values shuffles with in a row like [3 0 1 0 2;0 2 1 4 3...] like this

[Mohammad Abouali]

a=[1 0 1 0 1;0 1 1 1 1;1 1 0 1 1;1 1 1 1 1];
b=cumsum(a,2).*a;
disp('b:')
disp(b)

will print:

b:
     1     0     2     0     3
     0     1     2     3     4
     1     2     0     3     4
     1     2     3     4     5

Now shuffling:

shuffle=@(data) data(randperm(numel(data)));

for row=1:size(a,1)
  mask=logical(a(row,:));
  b(row,mask)= shuffle(b(row,mask));
end

disp('shuffled b:')
disp(b)

will print: (well it is random, so each time prints something different)

shuffled b:
     2     0     3     0     1
     0     1     3     4     2
     1     3     0     2     4
     4     5     3     1     2