parfor - how do I "slice" a variable? Can I?

I have a parfor loop that takes one row of a matrix and uses it for calculations.

I therefore am getting errors since I am calling this variable inside the iteration by writing "b = B(i,:)" to get the ith row. What do I do? I understand the problem, each worker is having to read B to find what b is, but I have no clue what to do to fix it or if anything even can be fixed.

Thanks for any help Mike

[Daniel Shub]

What error are you getting? I don't see why

b = B(i, :)

would cause an error, unless you are running out of memory.

[Edric Ellis]

Any chance you could post a self-contained example? "B(i,:)" should allow the variable B to be sliced, unless you're using B in some other way.

Answer 1

[Hin Kwan Wong]

Make sure the following requirements are satisfied:

• Type of First-Level Indexing — The first level of indexing is either parentheses, (), or braces, {}.
• Fixed Index Listing — Within the first-level parenthesis or braces, the list of indices is the same for all occurrences of a given variable.
• Form of Indexing — Within the list of indices for the variable, exactly one index involves the loop variable.
• Shape of Array — In assigning to a sliced variable, the right-hand side of the assignment is not [] or '' (these operators indicate deletion of elements).

For exacmple, you might have other instances where B is referenced with different indices not as B(i,:) (point 2)