False Position method GUI problems
Afficher commentaires plus anciens
I've wrote the code:
syms x;
s = input ('Function ');
s = char (s);
f = inline (s);
s_2 = diff (s, 2, 'x');
s_2=char(s_2);
f_2 = inline (s_2);
n = input ('Iteration number ');
a=input('interval: a ');
b= input ('interval: b ');
i=0;
if (f(a)*f_2(a)<0)
x=a;
while (i<=n)
x=x-(f(x)/f(x)-f(b)*(x-b));
i=i+1;
end
elseif (f(a)*f_2(a)>0)
x=b;
while (i<=n)
x=x-(f(x)/(f(x)-f(a))*(x-a));
i=i+1;
end
end
fprintf('x_9 false method position %f',x);
Works fine.
Here is the GUI code that i can't make it work
function rez_Callback(hObject, eventdata, handles)
ca = get(handles.cap_a, 'String'); %endpoint "a" of the interval
a = str2num(ca);
cb = get(handles.cap_b, 'String'); %endpoint "b" of the interval
b = str2num(cb);
nrit = get(handles.nr_iter,'String'); %number of iterations
N = str2num(nrit);
function = get(handles.edit_fct, 'String');
f = inline(function);
i = 0;
if(f(a)*f_2(a)<0)
x = a;
while (i<=n)
x = x-(f(x)/f(x)-f(b)*(x-b));
i=i+1;
end
elseif (f(a)*f_2(a)>0)
x=b;
while (i<=n)
x=x-(f(x)/(f(x)-f(a))*(x-a));
i=i+1;
end
end
set(handles.edit_rez, 'String', x); %i display the result in an edit text
because i have no idee how to put this
s_2 = diff (s, 2, 'x');
s_2=char(s_2);
f_2 = inline (s_2)
I tried but i failed every time.
How GUI looks like

Test function x^3-6*x^2+10*x-4
1 commentaire
Esraa Osama
le 19 Déc 2020
Hello sorry but can you help me with code of bisection method I need it for my project 🙆🏻♀
Réponse acceptée
Plus de réponses (0)
Catégories
En savoir plus sur Function Creation dans Centre d'aide et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!