Effacer les filtres
Effacer les filtres

Need a quick help on storing words according to lengths with struct

1 vue (au cours des 30 derniers jours)
Given a wordlist in cell array
wordlist={'blues';'rhyme';'armor';'dinosour';'book';'mail'......};
wordstruct=struct;
%%i am not sure how to proceed however it is organised such that the words are between four to 25, and I would like to do something like this,
wordstruct.4L={book mail ....}
wordstruct.5L={blues rhyme.....}
.
.
.
.
.
wordstruct.26L={whateveritisthatmightexist}
I almost given up on finding the right way to do it this way. Any help is very appreciated!

Réponse acceptée

Fangjun Jiang
Fangjun Jiang le 27 Nov 2011
You have to use wordstruct.L4, wordstruct.L5, etc. as '4L','5L' etc. are not valid name.
cellfun('islength',...) and then a for-loop should getting you there.
wordlist={'blues';'rhyme';'armor';'dinosour';'book';'mail'};
clear wordstruct;
Len=cellfun('length',wordlist);
for L=4:26
wordstruct.(['L',num2str(L)])=wordlist(Len==L);
end
  4 commentaires
Fangjun Jiang
Fangjun Jiang le 27 Nov 2011
Sorry, I meant cell2struct(). In fact, it doesn't have to be used. See update.
NUR KHAIRUNNISA rahimi
NUR KHAIRUNNISA rahimi le 27 Nov 2011
you are awesome!Thank you!

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