Array/Data Strucutre Returns Problem

I made a data structure as the following:

idols(1).groupname='2pm';

idols(1).nummembers = 6;

idols(1).gender = 'boys';

idols(1).debut = 2008;

idols(1).member(1).name = 'chansung';

idols(1).member(1).birthyear = 1990;

idols(1).member(1).height = 184;

idols(1).member(1).blood = 'B';

idols(1).member(2).name = 'junho';

idols(1).member(2).birthyear = 1990;

idols(1).member(2).height = 178;

idols(1).member(2).blood = 'A';

Then

name=idols(1).groupname

/////////////

The result is

name =

2pm

////////////

If I want the result to be the same as the input, i.e. name='2pm' How should I receive or change the value? Assuming that the method of making the data structure is not changed.

PS: It seems to be the case that if I make the data structure differently, it gives '2pm' instead of 2pm.

Answer 1

[Junaid]

I think you can't compare two string with == . You will get dimensions mismatch. As for string '2pm' the length = 3 and for 'SNSD' the length =4. You can use string compare function.

let say.

if (strcmp(idols(1).groupname, idols(2).groupname))
fprintf('Group is 2pm, or whatever you want');

end

Answer 2

[Junaid]

As I understand that

if you store

idols(1).groupname='2pm';

and when you type

idols(1).groupname

you get

2pm. But you are interested to get '2pm'. right ? If yes then it can be as simple as you store them with ' ' .

ex.

idols(1).groupname='''2pm''';

then if you type

idols(1).groupname

you will get

'2pm'

[Junaid]

Or you can store like this

idols(1).groupname= {'2pm' };

then when you type

idols(1).groupname

you get :

'2pm'

[Dong-Kyeong]

What I want to do is

function []=Func(idols,varargin)

if idols(1).groupname==varargin(1)

disp('Group is 2pm');

end

end

Func(idols,'2pm','SNSD')

Is it possible?

[Walter Roberson]

No. You cannot compare strings or cell arrays using "==" . To compare strings you should use strcmp() or strcmpi().

if strcmpi(idols(1).groupname, varargin(1))