Identify which row has a number which exceeds a number N

I have a code which finds the position of the rows having a zero or a duplicate number in any particular row in a matrix A. Here is the code:

b = any(~diff(sort(A,2),1,2),2) | any(z==0,2) ; % locate any zero or repeating number

A=[1 2 0
   19 5 6
   6 6 7
   8 9 3]

Result

b=[1
   0
   1
   0]

My question is how to modify this code for it to identify also any particular row having a number which exceeds a fixed number N.

N=16; % assume Fixed number N=16

A=[1 2 0
   19 1 4
   6 6 7
   8 9 3]

Expected result:

b=[1
   1 
   1
   0]

Can you please help me out?

Answer 1

[Joseph Cheng]

try

 any(A>=N,2)

so I don't know what z is but changing z to A i get the desired answer

 any(A>=16,2)|any(~diff(sort(A,2),1,2),2) | any(A==0,2)

[Amit Sookun]

It works!! Thank you Joseph! :)

Answer 2

[Andrei Bobrov]

any([A > N, A == 0 , ~diff(sort(A,2),[],2)],2)