How do you set a default reference for structure fields.

6 vues (au cours des 30 derniers jours)
Eric
Eric le 18 Juin 2015
Modifié(e) : Stephen23 le 19 Juin 2015
Suppose I have the structure "structure1" that has 3 fields a, b, c. I pass this structure to a function to perform some operations. I would like to setup the function as follows
function out = function(structure1)
% set structure 1 as the default field reference
?command? structure1
out = a + b*c;
I am trying to avoid
out = structure1.a + structure1.b*structure.c;
or
a = structure1.a;
b = structure1.b;
c = structure1.c;
out = a+b*c;
I seem to remember there was a command that did this in release 13 but I just cannot remember the command itself.
Thanks for your help,
Eric

Réponse acceptée

Tim
Tim le 18 Juin 2015
There's this one from the file exchange that does what you want:
I think you would just do:
v2struct(structure1);
And it would pull a b and c as variables.
  1 commentaire
Eric
Eric le 19 Juin 2015
Modifié(e) : Eric le 19 Juin 2015
Thanks, I will look into it.

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Plus de réponses (1)

Stephen23
Stephen23 le 18 Juin 2015
Modifié(e) : Stephen23 le 19 Juin 2015
You could use struct2cell and deal to allocate those field values to separate variables, but this depends on the order in which the fields were defined:
>> S.a = 1;
>> S.b = 2;
>> S.c = 3;
>> C = struct2cell(S);
>> [a,b,c] = deal(C{:})
a =
1
b =
2
c =
3
The most robust solution would be as you wrote in your question:
a = structure1.a;
b = structure1.b;
c = structure1.c;
  1 commentaire
Eric
Eric le 19 Juin 2015
Thank you. I will probably go with the second part sin alreadyce that is what I have already. The data structure I am dealing with is quite large and the work has been done already, I was just hoping to cut down on the number of lines and speed the script up.

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