Search entire multi level cell array for matching string

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Josh Welch
Josh Welch le 6 Août 2015
Modifié(e) : Cedric le 6 Août 2015
I am trying to search a cell of cell arrays for a matching string without using a for loop due to the inefficiency and speed. My first idea was to use an anonymous function and strip out the top layer iteratively of the cell array in the form of
cellfun(@(cell) cell{1}, MyCellofCellArray, 'UniformOutput', false);
However, let's say for example I have an uneven cell of cell array where
MyCellArray{1} = 1x1 cell,
MyCellArray{2} = 1x2 cell,
MyCellArray{3} = 1x3 cell.
If you try to use the aforementioned cellfun, you get an error "Index exceeds matrix dimensions" because MyCellArray{1} only contains a 1x1 cell. Anyone have any ideas or suggestions?
Thanks,
JWelch
  3 commentaires
Josh Welch
Josh Welch le 6 Août 2015
I just need to extract the index of the array element of the matching string. Each element of the array contains just one string.
i.e. MyCellArray{1} = {'str11'}, MyCellArray{2} = {'str21','str22'}, MyCellArray{3} = {'str31','str32','str33'}. I would like to find the indices of cell 'str32' in MyCellArray. The element is accessed via MyCellArray{3}{2} so 3, 2 would be the answer.
Cedric
Cedric le 6 Août 2015
Modifié(e) : Cedric le 6 Août 2015
Which version of MATLAB do you have? Also, are you search for unique keywords, for the first when there are multiple, or for all occurrences?

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James Tursa
James Tursa le 6 Août 2015
Modifié(e) : James Tursa le 6 Août 2015
Does this do what you want?
mystring = whatever string you are trying to find
MyCellArrays = [cellfun(@(x)x(:)',MyCellArray,'UniformOutput',false)];
NewCellArrays = [MyCellArrays{:}];
x = find(~cellfun(@isempty,strfind(NewCellArrays,mystring)));
n = cellfun(@numel,MyCellArray);
nsum = cumsum(n);
first = find(nsum>=x,1);
if( first == 1 )
second = x;
else
second = x - nsum(first-1);
end
The element is then MyCellArray{first}{second}
If the string is not guaranteed to be present, then test for x being empty before executing the remaining code.
  1 commentaire
Josh Welch
Josh Welch le 6 Août 2015
This code actually will work. I was hoping to get the indices from the original matrix but I can massage the rest of my code the same way to get the corresponding data with the same indices.
Thanks for your help!

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Plus de réponses (1)

Cedric
Cedric le 6 Août 2015
Modifié(e) : Cedric le 6 Août 2015
If you have 2015a or above, this can be an occasion for playing with the new REPELEM function:
linId = strcmpi( [MyCellArray{:}], 'str32' ) ;
lookup = repelem( 1:numel(MyCellArray), cellfun( @numel, MyCellArray )) ;
id = [lookup(linId), sum( lookup(1:find(linId) == lookup(linId)) )] ;
This produces
id =
3 2
  2 commentaires
Josh Welch
Josh Welch le 6 Août 2015
I tried this code which is extremeley elegant, but I don't have 2015. When I upgrade, REPELEM is definitely going in my bag of tricks... thanks for your input
Cedric
Cedric le 6 Août 2015
Modifié(e) : Cedric le 6 Août 2015
My pleasure! I discovered REPELEM last week actually, so I'm glad to have had this occasion for playing a bit with it. Just for those who don't have 2015a or above, here is the output of intermediary steps:
linId =
0 0 0 0 1 0
lookup =
1 2 2 3 3 3

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