Effacer les filtres
Effacer les filtres

How can I iterate through a list of files using dlmread()?

5 vues (au cours des 30 derniers jours)
Haydn Darragh
Haydn Darragh le 19 Août 2015
Commenté : Haydn Darragh le 19 Août 2015
I am able to load all files and manually change the name of the files to access each on individually, however when I try to use a for loop that changes the name of the file in the form of a changing string, I get the error message below:
"Error using dlmread (line 119) The file 'file1' could not be opened because: No such file or directory
Error in EbnoVsRange (line 19) Zero(i) = dlmread(fname,',',[26 2 26 2]);"
This is after I have loaded the files in, one of which is called 'file1'
The code I'm using is below:
file1 = 'C:\Users\....\range1cm.csv';
file2 = 'C:\Users\....\range2cm.csv';
file3 = 'C:\Users\....\range3cm.csv';
file4 = 'C:\Users\....\range4cm.csv';
file5 = 'C:\Users\....\range5cm.csv';
for i = 1:1:10
Zero(i) = dlmread(fname,',',[26 2 26 2]);
Thank You

Réponse acceptée

David Legland
David Legland le 19 Août 2015
Modifié(e) : David Legland le 19 Août 2015
The problem comes from you ask Matlab to open the file called 'file1', not the file whose name is stored in the variable file1.
In your case you can use the 'eval' function:
fname = eval(['file' num2str(1)]);
However, I would rather build the file name programmatically:
inputDir = 'C:\Users\...'
fname = fullfile(inputDir, sprintf('range%dcm.csv', i));
  1 commentaire
Haydn Darragh
Haydn Darragh le 19 Août 2015
This is great, thank you for your response. I have also implemented your other option for retrieving the files too. This will save many lines of code at the end of the day

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