Let us say I have a row vector with "n" number of rows.
e.g. [0 27 29 45 66]';
How can I write a command using a FOR loop, that adds the first element with the second element, then the second element with the third element and so on until it gets to the "n" number of rows.
And in the end adding up all those answers.
So like: (0+27)+(27+29)+(29+45)... and so on.
I'm only a beginner in MatLab and spent hours trying to figure this out. Hope you guys can help. Thanks for the help in advance. :D

 Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 12 Déc 2011

0 votes

aout = 0;
for i1 = 1:numel(a)-1;
aout = aout + a(i1) + a(i1+1);
end
without loop for..end
n = numel(a)
aout = sum(a(1:n-1)+a(2:n))

3 commentaires

Walter Roberson
Walter Roberson le 12 Déc 2011
sum(a(1:n-1)+a(2:n)) can also be expressed as
a(1) + 2*sum(a(2:n-1)) + a(n)
Mayu
Mayu le 12 Déc 2011
Is there a command to just display the last cumulative element.
when i try to display the "aout" it always comes out as the cumulative frequency throughout the whole array.
Sean de Wolski
Sean de Wolski le 12 Déc 2011
aout(end)

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Plus de réponses (2)

Shouvik Das
Shouvik Das le 12 Déc 2011

0 votes

Considering you need to store each intermediate output in another array. Let input array with n rows be inputArray
outputArray=[];
for i=1:length(inputArray)-1
outputArray(i)=inputArray(i) + inputArray(i+1);
end
Hope this helps.
Regards Shouvik

1 commentaire

Mayu
Mayu le 12 Déc 2011
Thanks, works wonderfully :D

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Anurag Pratap Singh
Anurag Pratap Singh le 25 Juin 2020
Modifié(e) : DGM le 4 Mar 2023

0 votes

Hi Mayu
You could use an extra array for storing every output let say addArr array and then add each elements of the addArr.
addArr = [];
for i = 1:length(inputArr)
addArr(i) = inputArr(i)+inputArr(i+1);
end
Then add each element of addArr
result = 0;
for i = 1:length(addArr)
result = result+addArr(i);
end
The result variable has the cummulative sum of all the elements in input array.
Thank you

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