split binary array based on value 1

Hi,

I have a binary array that I would like to split up into several others, each starting with a '1'. I almost have it to work, except the sizes do not match and mat2cell does not work. Please help me with the last bit, thanks!

Jasper

a = [ 1 0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]';

indices = find(a(:,1)~= 0); % gives 1,5,11,16 and is correct

sizes = diff([indices' size(a, 1)]);% gives 4,6,5,13 instead of 4,6,5,14!

mat2cell(a, sizes, size(a, 1)); % fail!

Answer 1

[Walter Roberson]

sizes = diff([indices' size(a, 1)+1])

Answer 2

[Image Analyst]

I don't see any splitting going on - it's not splitting the array into multiple other arrays. What I see is you counting the zeros and ones as a unit. If you have the Image Processing toolbox, you can just find the sizes of the 0's and add 1:

a = [ 1 0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]';
labeledArray = bwlabel(a==0);
measurements = regionprops(labeledArray, 'Area');
lengths = [measurements.Area]+1

In the command window:

lengths =
     4     6     5    14

Answer 3

[Azzi Abdelmalek]

a = [ 1 0 0 0 1 0 0 0 0 0 1 0 0 0 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0]';
ii1=strfind(a',[1 0]);
ii2=strfind([a' 1],[0 1]);
out=arrayfun(@(x,y) a(x:y),ii1,ii2,'un',0);
celldisp(out)