How to implement the counter (really simple)?

2 vues (au cours des 30 derniers jours)
Rengin
Rengin le 23 Sep 2015
Commenté : C.J. Harris le 23 Sep 2015
% Dear Users,
% My problem and simple script are as below:
clear all
clc
nrow=5;
ncolumn=3;
maxinfeas=1;
Infeasibles=zeros(nrow,1);
A=[-1 5 6 ; 4 2 3 ; 9 -7 1 ; 7 3 8 ; 4 0 1];
B=[75 60 90 ; 80 150 65 ; 20 10 40 ; 70 30 80 ; 100 20 35];
for nr=1:nrow
for nc=1:ncolumn
if A(nr,nc)>0 && B(nr,nc)<=100
Infeasibles(nr)=0;
else
Infeasibles(nr)=maxinfeas;
end
end
end
% Although expected matrix is Infeasibles=[1;1;1;0;1], Matlab adjusts it as Infeasibles=[0;0;0;0;0]
% How can I correct the code?
% Thanks a lot!

Réponses (2)

C.J. Harris
C.J. Harris le 23 Sep 2015
Modifié(e) : C.J. Harris le 23 Sep 2015
Infeasibles = any((A<=0) | (B>100),2);
  2 commentaires
Rengin
Rengin le 23 Sep 2015
Isn't it possible to put it into a for loop? It is more convenient for my whole script.
C.J. Harris
C.J. Harris le 23 Sep 2015
Sure, just update your original code, changing the line:
Infeasibles(nr)=0;
To:
Infeasibles(nr)=max(0,Infeasibles(nr));

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Thorsten
Thorsten le 23 Sep 2015
You can write
idx = ~(all(A > 0, 2) & all(B < 100, 2))
  1 commentaire
Rengin
Rengin le 23 Sep 2015
Isn't it possible to put it into a for loop. It is more convenient for my whole script.

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