Cubic Spline Interpolation and Plotting??? Question inside

2 vues (au cours des 30 derniers jours)
Nicole Bonino
Nicole Bonino le 25 Sep 2015
Modifié(e) : WAT le 25 Sep 2015
Use cubic splines to fit the data bellow. Repeat the calculation but now set the derivatives at the end points to zero. Compare the two profiles.
x=[0 2 4 7 10 12]; y=[20 20 12 7 6 6];
pp=spline(x,y)
This is the code I have so far but I keep getting an error when trying to plot it. I tried plotting using this code:
plot(x,pp,y) and again with plot(pp,x,y) and plot(x,y,pp)
the output I get for pp is:
form: 'pp'
breaks: [0 2 4 7 10 12]
coefs: [5x4 double]
pieces: 5
order: 4
dim: 1
But I keep getting error messages. I tried following the examples in the doc but it isn't working.
  3 commentaires
Nicole Bonino
Nicole Bonino le 25 Sep 2015
I had my code in before, I dont know why it didnt save. I fixed it.
WAT
WAT le 25 Sep 2015
Modifié(e) : WAT le 25 Sep 2015
Read the documentation for spline()
You're using the form of the function which takes only two input arguments, which returns the coefficients for the spline functions. You can't plot coefficients, you need to plot function values.

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WAT
WAT le 25 Sep 2015

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