Printing out a variable in while loop?

2 vues (au cours des 30 derniers jours)
Nick Haufler
Nick Haufler le 12 Oct 2015
Commenté : Nick Haufler le 12 Oct 2015
In my document, Im pretty sure my code is right, I just dont get why my estimated and actual cube root values come out the same. I dont think theyre supposed to be that way, and I have no idea what variable to print out for the actual cube root fprintf statement. Would i need an equation for an actual cube root, although the directions dont say anything about that. Right now, I am just greatly confused, the help i have received so far isnt clicking for me.

Réponse acceptée

Geoff Hayes
Geoff Hayes le 12 Oct 2015
Nick - your answers come out the same since you are writing out the same variable for each print statement:
fprintf('The actual cube root is %0.3f\n', Estimate)
fprintf('The estimate of the cube root is %0.3f\n', Estimate)
The actual cube root of the input number would be
fprintf('The actual cube root is %0.3f\n', x^(1/3));
where x is the number that you are trying to compute the cube root of. For example,
x = input('Please enter a number:');
will allow the user to enter a number that he or she wishes to find the cube root of. Note that in your code you do
CubeRoot=input('Please enter a number:')
The above line is misleading since the number entered by the user is not the cube root but is the number that they wish to find the cube root of.
  1 commentaire
Nick Haufler
Nick Haufler le 12 Oct 2015
Geoff- Thank You VERY MUCH! I finally understand it. I do see what you were saying about my input statements. I really appreciate your help. Thanks again!

Connectez-vous pour commenter.

Plus de réponses (1)

Steven Lord
Steven Lord le 12 Oct 2015
As John stated two days ago, DON'T KEEP POSTING THE SAME QUESTION REPEATEDLY!
Walter TOLD you what was wrong in another post from two days ago. Reread what he wrote.

Catégories

En savoir plus sur Programming dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by