Going from a Matrix of months to a date.

Days_into_Month = cell(n,1);
Month = char(Month(1:n,1));
for d = (1:n)'
switch Month(d,1)
    case {'Jan'}
        Days_into_Month(d,1) = {Total_Days(d,1) +6};
    case {'Feb'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 24};
    case {'Mar'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 53};
    case {'Apr'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 84};
    case {'May'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 114};
    case {'Jun'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 145};
    case {'Jul'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 175};
    case {'Aug'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 206};
    case {'Sep'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 237};
    case {'Oct'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 267};
    case {'Nov'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 298};
    case {'Dec'}
        Days_into_Month(d,1) = {Total_Days(d,1) - 328};
    case {'Ja_'}            
        Days_into_Month(d,1) = {Total_Days(d,1) - 359};
        Actual_Year = Actual_Year + 1;
end
end

I am looking for my matrix to come back with different numbers varying to each month.

Month = 

      'Mar'
      'Dec'
      'Oct'
      'Oct'
      'May'
      'Jul'
      'Dec'

This is the current month data set that I have and i need Days_into_Month to be a result of Total_Days(d,1) subtract the corresponding number.

Answer 1

[Walter Roberson]

dayoff = [6, -24, -53, -84, .... -359];
[tf, monidx] = ismember(Month, {'Jan', 'Feb', 'Mar', .... 'Dec', 'Ja_'});
Days_into_Month = Today_days + dayoff(monidx);