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How do I deal with this function handel error?

3 vues (au cours des 30 derniers jours)
Ruten9
Ruten9 le 25 Oct 2015
Clôturé : MATLAB Answer Bot le 20 Août 2021
my height file:
function h = height(t)
h = @(t) ((-9.8).*(2.^(-1))).*(t.^2) + 125.*t + 500;
h(h<0) = 0;
if h(t) <0
then h=0
end
end
My main file:
clear all; clc;
t = 0:.01:35;
h = height(t)
%Part C (maxima)
[xpsudeomax,ymax] = max(h(t));
xrealmax = t(ymax);
maxfunction = [xrealmax,ymax];
%fminbnd function
[xmax2,ymaxpsudeo]= fminbnd(@(t) (-1.*h(t)),0,30);
yrealmax = -1.*ymaxpsudeo;
format long g
fminbndmax = [xmax2,yrealmax] ;
%Part D
[xzero,ypsuedozero]= fzero(@(t) h(t),20);
yrealzero = round(ypsuedozero);
ZERO = [xzero,yrealzero];
%Part B (height vs time)
figure;
plot(t,h(t),'blue',xmax2,yrealmax,'go','LineWidth',2);
hold on;
plot(xzero,yrealzero,'r.','MarkerSize',20);
title('Rocket Trajectory');
ylabel('altitude [m]');
xlabel('time [sec]');
axis([0 35 0 1500]);
legend('height','max','ground','location','ne')
I keep getting the
"Undefined operator '<' for input arguments of type 'function_handle'.
Error in height (line 7)
h(h<0) = 0;"
How would I resolve this? I got everything on my graph right, but I can't get the flat,horizontal line to appear at the very end.
  3 commentaires
Ruten9
Ruten9 le 25 Oct 2015
How would I go about that for this problem? I'm very lost.

Réponses (1)

Gareth Thomas
Gareth Thomas le 25 Oct 2015
Try to remove: h(h<0) = 0;
From your height function. This will help you.
  2 commentaires
Ruten9
Ruten9 le 25 Oct 2015
My hw says that it should be there. I'm not sure why though.
Walter Roberson
Walter Roberson le 26 Oct 2015
Then either your "hw" is wrong or you have misinterpreted your "hw" or you have implemented in a way that you are not intended to use.

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