creating a temporary variable
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This is a quick question. Compare
A = sparse(...); B = A - C;
and
B = sparse(...) - C;
Memory-wise spoken, is there a difference? Will the second one use less memory because I'm not creating a variable?
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Walter Roberson
le 3 Jan 2012
There will be very little memory difference. For a transient value, MATLAB creates everything about the storage except the symbol table entry with the name and a pointer to the descriptor.
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Walter Roberson
le 3 Jan 2012
As far as I know, MATLAB only uses memory "in-place" when the same variable appears in a function call and in the assignment of the results from that call. There was another condition as well but I have forgotten it now.
I'm thinking it might have been Rick Rossom who listed the conditions in a comment, but it might have been someone else at MathWorks.
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Nicholas
le 3 Jan 2012
Did you try using tic toc?
tic
A = sparse(magic(3));
B = A - C;
disp(toc)
tic
B = sparse(magic(3)) - C;
disp(toc)
In any case the result depends on matrix dimensions and matrix initialization. If you want to improve memory management you should initialize a matrix/vector first and than try to improve matrix calculation.
3 commentaires
Nicholas
le 3 Jan 2012
If you are interested so deeply in memory allocation you should write your code in C and do not use matlab.
You can not see under the hood in matlab..
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