using For loop to represent positive intergers with the corresponding #. And modifying the script to write out a triangular pattern with a decreasing number of #'s on each successive line

%  a script which reads in a positive integer 
%  and writes out the corresponding number of “#” characters on one line

num=1;

fprintf('This program reads any positive integer');

while num>0
    % print out corresponding number of #'s char on one line
    fprintf('%d\n', num);

[TastyPastry]

Post your attempt at the problem.

Answer 1

[Thorsten]

Use input to get number, and repmat to replicate '#' number times. To count down, use

for i=num:-1:1

To display num #'s use

disp(repmat('#', 1, num))

I think these are enough hints to complete the task yourself.