deleting words from a cell array

5 vues (au cours des 30 derniers jours)
James Connor
James Connor le 11 Nov 2015
if I have a cell array
x={'areach';'aread';'areal';'areality';'arean';'arear';'areasoner';'areaway';'areca';'arecaceae'}
y='a'
word='areach'
How do I delete all the words from x that do not have y in the positions it appears in word
for example 'a' appears as the 1st and 4th letter of word, delete all words from dictionary that do not have 'a' as their 1st and 4th position letters. so x would become
x={'areach';'aread';'areal';'areality';'arean';'arear';'areasoner';'areaway'}
(it got rid of 'areca' and 'arecaceae)

Réponse acceptée

Mohammad Abouali
Mohammad Abouali le 11 Nov 2015
Modifié(e) : Mohammad Abouali le 11 Nov 2015
x={'areach';'aread';'areal'; ...
'areality';'arean';'arear'; ...
'areasoner';'areaway';'areca'; ...
'arecaceae'};
y='a';
word='areach';
% This line does the trick;
x=x(cellfun(@(c) all(c(find(word==y))==y),x))
x =
'areach'
'aread'
'areal'
'areality'
'arean'
'arear'
'areasoner'
'areaway'
Note that the position 1 and 4 are not hard coded. They are defined based on the y and word
  1 commentaire
Mohammad Abouali
Mohammad Abouali le 16 Nov 2015
Modifié(e) : Mohammad Abouali le 16 Nov 2015
you can also use
x=x(cellfun(@(c) all(c(word==y)==y),x))
i.e. without using find().

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Plus de réponses (1)

bio lim
bio lim le 11 Nov 2015
x={'areach';'aread';'areal';'areality';'arean';'arear';'areasoner';'areaway';'areca';'arecaceae'};
for n = 1 : length(x)
if ~strcmp(x{n}(4),'a')
x{n}=[];
end
end

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