Error with find command for a matrix

20 vues (au cours des 30 derniers jours)
Jason Fender
Jason Fender le 5 Mar 2011
Hello,
I have data points from a DAQ with a time and signal. My goal is to find the period of my data points. To do this, I wanted to find the maximum peak value and the minimum peak value. If I have these, I should be able to find the corresponding time to those values, which would be half my period since the shape of my data is basically a repeating sine wave.
Here is what I have so far:
_____________________________________________________
clc;
format short
%Compose matrix with time vecotr and signal vector
Test1Signal1=[Test1_Time, Test1_Signal1];
%Find the maximum value
a=max(Test1Signal1,[],1);
a=a(:,2)
%Find the mimumum value
b=min(Test1Signal1,[],1);
b=b(:,2)
%Find the time that corresponds to the maximum value (a)
[r c]=find(Test1Signal1,a)
%Find the time that corresponds to the minimum value (b)
[r c]=find(Test1Signal1,b)
_____________________________________________________
The problem is, I keep getting an error. The error I'm getting is as follows:
??? Error using ==> find Second argument must be a positive scalar integer.
Error in ==> Test1 at 16 [r c]=find(Test1Signal1,a)
I cannot figure out why the code is giving me this error. The value of a (the maximum) is a positive number. Again, I want this to give me the row and column that corresponds to the maximum value so that I can find the time from the original matrix that matches this value.
If that can get figured out, I might have another problem. The minimum value is a negative number. I'm not sure if the find command is going to work on a negative number, but that might be another problem once I get there. Any help would be greatly appreciated.
Thanks

Réponses (2)

Paulo Silva
Paulo Silva le 5 Mar 2011
[r c]=find(Test1Signal1==a)
instead of
[r c]=find(Test1Signal1,a)

Walter Roberson
Walter Roberson le 5 Mar 2011
find() does not take two arguments that are an array to search in and the value to search for. The first argument to find() is interpreted as a logical condition with all non-zero values corresponding to "true". Usually find() then returns the locations of all of the positions that are considered true, but find() takes an optional numeric argument that must be a positive integer that tells it how many indices to return. Thus, find(Test1Signal1,a) is requesting that find() return the first "a" locations of Test1Signal that are non-zero. For example, find(Test1Signal1,2) would return the indices of two non-zeros.
The code you are looking for is
[r c] = find(Test1Signal1==a)
I suggest, though, that you consider
[a, minloc] = min(Test1_Signal1)
[b, maxloc] = max(Test1_Signal1)
and then the times would be Test1_Time(minloc) and Test1_Time(maxloc)
Your logic is fragile, though: due to noise or due to the sampling rate not being exactly a multiple of your frequencies, the minimum over the entire signal is not necessarily in the same period as the maximum value.

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