hi!! I am at the end of my project, please help me.

I have two rows ft=[0 0 -1 0 -1 -1] and st=[0 0 -1 0 0 -1] I want the position of equal elements i.e for 0 when comparing both the rows, I want position as 1 2 4 as my answer.

ft=[0 0 -1 0 -1 -1]
st=[0 0 -1 0 0 -1]
pos= 1 2 4 (expected answer).

I am trying to use

pos=find(bitand(ft,st)==0);

but getting this error

Double inputs must have integer values in the range of ASSUMEDTYPE.

I know this error is because of '-1'. Is there any other way to find the position.

Answer 1

[Walter Roberson]

pos = find( ft==0 & st==0 );

[Rutika Titre]

Thank-you Sir,It worked.In this I got the position of equal number. For getting the number of equal elements I am using

mxt=sum(bitand(~ft,~st));
ft=[0 0 0 0 0]
st=[0 0 -1 0 0]
mxt=4;

suppose my

ft=[0 0 -1 0 -1 -1]
st=[0 0 -1 0 0 -1]
mxt=3;

will my logic of sum and bitand is it correct?? Please do let me know , and is there any easier way to my ouput?

[Walter Roberson]

mxt = sum(ft == st);

[Rutika Titre]

Thank-You sir, I actually wanted for only zero elements not -1. That is why I had used ~ sign.What you suggested is for even -1 I want only for 0 elements.Like in second example I want mxt=3 ; Your answer is giving me mxt=5.

[Rutika Titre]

sir I have used mxt = sum(ft==0 & st==0);this is working. Thank-you for your help.It helped me a lot as I was working on it since a month.I hope now my project will end till tomorrow.Thank you thank you thank you.