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index out of bound

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sweta arya
sweta arya le 20 Jan 2016
Clôturé : MATLAB Answer Bot le 20 Août 2021
intial_image=zeros(180,1);
for i=1:180
intial_image(i)=i;
end
y =zeros(30,1);
y = datasample(intial_image,30);
disp(y(2,1));
size3=0;
nBins=8;
Nind=0;
h1=0;
count=0;
for i=1:30
if(numel(y)==30)
jpgFileName = strcat('C:\Users\priya\Desktop\Fashion Photography\',num2str(y(i)), '.jpg');
I= imread(jpgFileName);
[row,col,m]=size(I);
size3=size3+ row*col;
count=count+1;
end
giving error:
can not access y(2,1) because numel(y)=1.
  2 commentaires
Stephen23
Stephen23 le 20 Jan 2016
Please show us all of the error message. This means all of the red text.
Stephen23
Stephen23 le 20 Jan 2016
The code needs to be simplified. Replace this:
initial_image=zeros(180,1);
for i=1:180
intial_image(i)=i;
end
with this:
initial_image = (1:180).';
There is no point in preallocating y like this:
y =zeros(30,1);
because it is completely reallocated on the very next line:
y = datasample(...)

Réponses (1)

Walter Roberson
Walter Roberson le 20 Jan 2016
Whatever
datasample(intial_image,30)
is, it is resulting in a scalar.
What is the result of
which -all datasample
? Is it from the Statistics Toolbox or does it resolve to one of your own routines?

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