fft error: Not enough input arguments.
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Someone can help me in this code for know de heart frequency.
function homoFreq(y,Fs,nfft)
% x is input signal
% nfft is number of fft points
Fs = 16000;%sampling rate
% subplot(2,1,1),plot(x);
% title('Waveform'), xlabel('Time (ms)'), ylabel('Amplitude');
[y,Fs]=wavread('*.wav'); %* is for file name
t=((1:length(y))-1)/Fs;
figure();
plot(t,y); %only for check
ht=fft((y.*hamming(length(y))),nfft); %nfft point -----> fft error in this line
freqAxis=Fs/2*length(ht)/Fs;
f=(0:freqAxis)*Fs/length(ht);
% subplot(2,1,2);
spec = 20*log10(abs(ht(1:length(f))));
plot(f,spec);ylim([-50 35]);
title('Spectrum'), xlabel('Frequency'),ylabel('Log Magnitude');
[pks,locs] = findpeaks(spec);
for m = 5:5,
differ(m-4) = locs(m)-locs(m-1);
%finding the difference between 5th...
%and 4th peak of the spectrum
end
pitchFreq = mean(differ)*Fs/nfft;
fprintf('Pitch Frequency in Frequency Domain = %gHz\n', pitchFreq)
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Walter Roberson
le 20 Jan 2012
You need to invoke
homoFreq([], [], NFFT)
where NFFT is the number of points you want to use for the fft.
3 commentaires
Dr. Seis
le 20 Jan 2012
He is simply suggesting you replace "NFFT" with the number of points you want to use. For example:
homeFreq([],[],1024)
The number you replace NFFT with depends on if you want to truncate "y", keep "y" the same length, or pad "y" with zeros until its length is equal to NFFT.
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Dr. Seis
le 20 Jan 2012
When you run the function as "homFreq" (with no input arguments) from the command line (or from the editor) you aren't defining "nfft" before it is being called at line 12.
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