Need help in coding this summation, please.

13 vues (au cours des 30 derniers jours)
Luciano Campos
Luciano Campos le 11 Mar 2016
Commenté : Ced le 12 Mar 2016
Hi,
Can anybody help me with coding this summation into matlab, please:
where J is (3x6), A is (6x6) and Phi is (3x3x9).
I've tried with this code:
% for ii=1:hor
for mm=1:ii
G(:,:,ii)=sum(kron(J*A'^(ii-mm),Phi(:,:,mm)),3);
end
end %
but it doesn't seem to work, as I get incorrect results. I think the mistake is in the sum function, but I don't know other way of coding the summation (cumsum function doesn't work either).
I'd really appreciate some help here, as I'm completely stuck.
best,
  3 commentaires
Luciano Campos
Luciano Campos le 11 Mar 2016
Hi Ced, Thanks for your comment. I tried what you suggest, but it still won't work. The original formula is correct. If you develop the original summation you get:
I think the problem is that I don't know how to sum up consecutive terms as neither sum nor cumsum function seem to work.
Thanks for your help,
best,
Ced
Ced le 11 Mar 2016
Modifié(e) : Ced le 11 Mar 2016
I just found it strange to start G indexing a 1, but Phi indexing at 0.
Yeah, I messed up, sorry. Your original equation looks correct to me, but yes, you sum up too much. With sum, for each mm, you sum up over all of Phi again, which is not what you want.
Assuming you initialize G with zero:
for ii=1:hor
for mm=1:ii
G(:,:,ii) = G(:,:,ii) + kron(J*A'^(ii-mm),Phi(:,:,mm));
end
end

Connectez-vous pour commenter.

Réponse acceptée

Walter Roberson
Walter Roberson le 12 Mar 2016
Is the x in a circle indicating cross-product or is it indicating exclusive or?
  1 commentaire
Ced
Ced le 12 Mar 2016
I believe it stands for the tensor product, hence the kronecker operator.

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Mathematics dans Help Center et File Exchange

Tags

Aucun tag saisi pour le moment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by