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suppressing output from user defined function

88 vues (au cours des 30 derniers jours)
Michael
Michael le 25 Mar 2016
Commenté : Voss le 25 Fév 2024
function f=fib(n);
f=ones(n,1);
for i=1:n-2;
f(i+2,1)=f(i+1,1)+f(i,1);
end;
i have this function to calculate fibbonaci sequence, but i get outputs despite having semicolons on everything.
Can anyone tell me why?

Réponse acceptée

Jonathan Chin
Jonathan Chin le 25 Mar 2016
When you call your function use a semi colon at the end of the function to suppress the output.
try f=fib(n) and f=fib(n); in the command line to see the results
  1 commentaire
Michael
Michael le 25 Mar 2016
Modifié(e) : Michael le 25 Mar 2016
worked. i'm an idiot -_- Thanks man.

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Plus de réponses (1)

Walter Roberson
Walter Roberson le 25 Mar 2016
You have to put a semi-colon in the line that calls fib() to prevent the default output
abc = fib(19)
fib is called and returns an expression that is assigned to the variable, but the default action for assignment is to also display the result of the assignment. You would need
abc = fib(19);
to suppress it.
This is not under the control of the called function, which does not have control by the time MATLAB makes the decision about whether to output or not.
  5 commentaires
Yevgeniy Gorbachev
Yevgeniy Gorbachev le 25 Fév 2024
@Voss Exactly the behavior I'm looking for, thank you!
Voss
Voss le 25 Fév 2024
You're welcome!

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