How to generate a random matrix with conditions?

How to generate a matrix ( n x m ) where i need this number represent a number of ones in each row like this

A = [ 2 3 1
      3 1 1
      4 1 0
      2 2 0 ]

I need to generate a matrix like this

    X = [ 1 1 0 1 1 1 0 1
          1 1 1 0 1 0 0 1
          1 1 1 1 0 0 1 0
          0 1 1 0 0 0 1 1 ]

Where every numbers in matrix A must be at least zero between its numbers of one

[Steven Lord]

It sounds like the poster wants something like run-length decoding but where only the length of the runs of 1's are given and it's assumed there are 0's between those runs. But you're right, the poster needs to clarify the rules for how many 0's should be between the runs. It's not just one 0 between each run, as seen in rows 2, 3, and 4.

Answer 1

[Azzi Abdelmalek]

It's almost what you are asking for!

A = [ 2 3 1
  3 1 1
  4 1 0
  2 2 0 ]
[n,m]=size(A);
ii=max(sum(A,2));
no=ii+m-1;
out=zeros(n,no);
for k=1:n
  r=A(k,:);
  nz=no-sum(r);
  q=num2cell(zeros(1,m-1));
  idx=randi(m-1,1,nz-m+1);
  for kk=1:numel(idx)
          q{idx(kk)}(end+1)=0;
  end
  aa=[];
  for pp=1:m-1
      aa=[aa ones(1,r(pp))  q{pp}];
  end
  aa=[aa ones(1,r(end))];
  out(k,:)=aa;
end
out

Answer 2

[Andrei Bobrov]

[m,n] = size(A);
X = zeros(m,sum(A,2) + n - 1);
a = arrayfun(@(x)ones(1,x),A,'un',0);
Xc(:,1:2:2*n-1) = a ;
Xc(:,2:2:end)  = {0};
for ii = 1:m
    b = [Xc{ii,:}];
    X(ii,1:numel(b)) = b;
end

Answer 3

[Azzi Abdelmalek]

I think this is What you want:

 A = [ 2 3 1
    3 1 1
    4 1 0
    2 2 0 ]
[n,m]=size(A);
ii=max(sum(A,2));
no=ii+m-1;
out=zeros(n,no);
for k=1:n
    r=A(k,:);
    nz=no-sum(r);
    q=[ cell(1) num2cell(zeros(1,m-1)) cell(1)];
    idx=randi(m+1,1,nz-m+1);
    for kk=1:numel(idx)
        q{idx(kk)}(end+1)=0;
    end
    aa=q{1};
    for pp=1:m
        aa=[aa ones(1,r(pp))  q{pp+1}];
    end
    out(k,:)=aa;
end
out

[Firas Al-Kharabsheh]

i want in each run give me another solution like this

first generation out = [ 1 1 0 1 1 1 0 1 
                         1 1 1 0 1 0 1 0
                         1 1 1 1 0 1 0 0
                         1 1 0 1 1 0 0 0 ]

second generation out =[ 1 1 0 1 1 1 0 1
                         0 1 1 1 0 1 0 1
                         0 1 1 1 1 0 1 0
                         0 1 1 0 1 1 0 0]

third generation out = [ 1 1 0 1 1 1 0 1
                         0 1 1 1 0 1 0 1
                         0 1 1 1 1 0 0 1
                         0 0 1 1 0 0 1 1 ]

when i create a large matrix A there is may be more then one zeros between number like the third generation in last row

[Azzi Abdelmalek]

Ok, have you tested my code? What is the problem with it? You said it's random, then why you are asking for specific result?

[Firas Al-Kharabsheh]

when i run the code in every time the same result appear ? why give me the same result???

[Azzi Abdelmalek]

No, I am not getting the same result

First run

     1     1     0     1     1     1     0     1
     1     1     1     0     1     0     0     1
     0     1     1     1     1     0     1     0
     1     1     0     1     1     0     0     0

Second run

     1     1     0     1     1     1     0     1
     1     1     1     0     0     1     0     1
     1     1     1     1     0     1     0     0
     1     1     0     0     1     1     0     0

Third run

     1     1     0     1     1     1     0     1
     1     1     1     0     0     1     0     1
     1     1     1     1     0     0     1     0
     0     0     1     1     0     1     1     0

[Firas Al-Kharabsheh]

if i have this matrix for the column how can generate it like the row matrix

B = [ 0 1 2 1    represent the column number 
      3 2 3 2
      1 2 1 1 ]

[Azzi Abdelmalek]

I didn't understand your question

[Firas Al-Kharabsheh]

How to generate a random matrix ( n x m ) where i need this number represent a number of ones in each column like this

 B = [ 0 1 2 1
       3 2 3 2
       1 2 1 1 ]

I need to generate a matrix like this

 y = [ 0 1 1 1
       1 0 1 0
       1 1 0 1
       1 1 1 1
       0 0 1 0
       1 1 1 0
       0 1 0 0
       0 0 1 1 ] 

 Where every numbers in matrix A must be at least zero between its numbers of one

[Azzi Abdelmalek]

You can use the same code, instead of B, use the transpose of B, and transpose the result.

B = [ 0 1 2 1
     3 2 3 2
     1 2 1 1 ]
A=B';  % Transpose B
[n,m]=size(A);
ii=max(sum(A,2));
no=ii+m-1;
out=zeros(n,no);
for k=1:n
  r=A(k,:);
  nz=no-sum(r);
  q=[ cell(1) num2cell(zeros(1,m-1)) cell(1)];
  idx=randi(m+1,1,nz-m+1);
  for kk=1:numel(idx)
      q{idx(kk)}(end+1)=0;
  end
  aa=q{1};
  for pp=1:m
      aa=[aa ones(1,r(pp))  q{pp+1}];
  end
  out(k,:)=aa;
end
out=out'  % Transpose the result

[Firas Al-Kharabsheh]

how can i combine the matrix A and Matrix B to generate the random Matrix ?

( Combine the two code to generate a random matrix )

[Azzi Abdelmalek]

You need to post another question.

[Firas Al-Kharabsheh]

http://www.mathworks.com/matlabcentral/answers/278135-how-can-i-combine-the-matrix-a-and-matrix-b-to-generate-the-random-matrix