Effacer les filtres
Effacer les filtres

find result from multiple if and range value

2 vues (au cours des 30 derniers jours)
badrul hisham
badrul hisham le 10 Avr 2016
Modifié(e) : Andrei Bobrov le 10 Avr 2016
hello, can someone help me? i have a set of range and i need the number produced from the the range. example: if i input a value of 0.17,it will find 0.17 is in which range (in this case it is in between 0.138 to 0.205) and then it will display the number of that range category which is 6.0
0.0 To 0.068 = 7.0
0.069 To 0.137 = 6.5
0.138 To 0.205 = 6.0
0.206 To 0.274 = 5.5
0.275 To 0.342 = 5.0 .
0.343 To 0.410 = 4.5
0.411 To 0.479 = 4.0
0.480 To 0.547 = 3.5
0.548 To 0.615 = 3.0
0.616 To 0.684 = 2.5
0.685 To 0.752 = 2.0
0.753 To 0.821 = 1.5
0.822 To 0.890 = 1.0

Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 10 Avr 2016
Modifié(e) : Azzi Abdelmalek le 10 Avr 2016
Edit2
r=[0.0 .068 7.0
0.069 0.137 6.5
0.138 0.205 6.0]
a=0.032
b=mat2cell(r(:,1:2),ones(size(r,1),1),2)
idx=cellfun(@(x) x(1)<=a & x(2)>=a,b)
sprintf('the range of a is %0.1f',r(idx,3))
  5 commentaires
Azzi Abdelmalek
Azzi Abdelmalek le 10 Avr 2016
Look again at edited answer. I think this is the good one
badrul hisham
badrul hisham le 10 Avr 2016
thank you so much for your help sir. this works perfectly now

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Plus de réponses (1)

Andrei Bobrov
Andrei Bobrov le 10 Avr 2016
Modifié(e) : Andrei Bobrov le 10 Avr 2016
x =[ 0 7.0000
0.0690 6.5000
0.1380 6.0000
0.2060 5.5000
0.2750 5.0000
0.3430 4.5000
0.4110 4.0000
0.4800 3.5000
0.5480 3.0000
0.6160 2.5000
0.6850 2.0000
0.7530 1.5000
0.8220 1.0000];
t = 0.890;
a = rand(30,1)*t;
[~,~,bin] = histcounts(a,[x(:,1);t]);
out = x(bin,2);

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