How to count no. of time state occur in sequence and then divide by sequence no.?
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Suppose I have a sequence 1,3,3,1,2,1,4,2,3,1,4,2,4,4,4,3,1,2,5,1 I have to count no. of times each state occur and then divide by sequence length and then take product, here 1 occur 6 times, 2 for 4, 3 for 4, 4 for 5 and 5 for 1 times occurring and sequence length is 20, so my final answer should be (6/20)*(4/20)*(4/20)*(5/20)*(1/20)=0.00014.
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Andrei Bobrov
le 7 Mai 2016
a =[1,3,3,1,2,1,4,2,3,1,4,2,4,4,4,3,1,2,5,1];
[a1,~,c] = unique(a);
out = prod(accumarray(c,1)/numel(a));
Azzi Abdelmalek
le 7 Mai 2016
Modifié(e) : Azzi Abdelmalek
le 7 Mai 2016
v=[1,3,3,1,2,1,4,2,3,1,4,2,4,4,4,3,1,2,5,1]
out=prod(nonzeros(accumarray(v',1))/20)
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