for loop for variables
22 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Nachiket Patki
le 9 Mai 2016
Modifié(e) : Stephen23
le 12 Sep 2023
I have written one code as follows,
for i=1:10
Ai=i;
fprintf('A is: %d \n',Ai)
end
what i want to achieve from here is, I want to store 1,2,3..10 in variables A1,A2,A3...A10. But the code i have created is giving me Ai as variable instead A1,A2...etc and storing Ai=10 at the end.(It has also created row vector A=[1:10])
Réponse acceptée
Azzi Abdelmalek
le 9 Mai 2016
Modifié(e) : Azzi Abdelmalek
le 9 Mai 2016
It's not a good idea to create variables A1,A2, ..., An. The array A=1:10 contains all your data. Why to create 10 variables, when one variable is sufficient
1 commentaire
Plus de réponses (1)
Weird Rando
le 9 Mai 2016
@Stephen: Haha I read the same thing somewhere online. But that didn't stop me :3
for i=1:10
eval(sprintf('A%i = i',i))
end
3 commentaires
Stephen23
le 9 Mai 2016
Modifié(e) : Stephen23
le 12 Sep 2023
@Scott: this is how it often goes:
- beginner: I have a great idea!
- experienced user: what?
- b. I will access my variables dynamically!
- e. Don't do that, it is inefficient, complex, buggy, and hard to debug. Here is why...
- b. No! I am really cunning, and I know more than every experienced user who is advising me to use better, more reliable methods! I even know better than TMW, who wrote a whole page about avoiding dynamic variable names.
- e. Here are some better ways to...
- b. I am so great, it works!!!
- e. sigh.
Three years later:
- slightly-more-experienced beginner: damn, I have to rewrite all of this awful, slow, buggy code that I wrote! And I have to unlearn all these bad habits!
Weird Rando
le 10 Mai 2016
It been three years, and yeah that did happen. Can't even understand what I code.
Voir également
Catégories
En savoir plus sur Whos dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!