How to have an eq. with an unknown?

8 vues (au cours des 30 derniers jours)
Will
Will le 8 Fév 2012
Hi
I would like to write
x0+a*s1=x1 but keeping a as an unknown so that if I replace with values, I get:
[1; 1]+a*[1; 0]=[1+a; 1]
Is this possible?

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Réponses (2)

Sean Lawson
Sean Lawson le 8 Fév 2012
As far as I know, not possible...
Walter Roberson
Walter Roberson le 8 Fév 2012
Symbolic toolbox.
syms x0 x1 a s1
x1 = x0 + a * s1;
subs(x1, {x0, s1}, [1;1], [1;0])

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