How to split a matrix based on indexing

I have a matrix (e.g. 16x11 double) that I want to split up into smaller matrices. I have created a index vector of zeros and ones (e.g. 16x1). Every time there is a one, I would like to split the matrix at this point. So if the 1's appear in row 1,5,12 I would need 3 matrices created from the original (so rows 1 to 4, 5 to 11, 12 to end). It would be useful to increment the matrix name too, like Data1, Data2, Data3. I think this needs to be a for loop? I need to repeat this on numerous sets of data with differing amounts of 1's in my index vector.

[per isakson]

"Data1, Data2, Data3" &nbsp usually triggers a link to &nbsp How can I create variables A1, A2,...,A10 in a loop?

Answer 1

[per isakson]

Two ways, arrayfun and for-loop

M = repmat( transpose([1:16]), [1,11] );
ix1 = [1,5,12]; 
ix2 = [ix1(2:end)-1,size(M,1)];
data = arrayfun( @(r1,r2) M(r1:r2,:), ix1, ix2, 'uni', false );
cac = cell( 1, length(ix1) );
for jj = 1 : length(ix1)
   cac{jj} = M(ix1(jj):ix2(jj),:); 
 end

and check the results

>> data
data = 
    [4x11 double]    [7x11 double]    [5x11 double]
>> data{2}
ans =
     5     5     5     5     5     5     5     5     5     5     5
     6     6     6     6     6     6     6     6     6     6     6
     7     7     7     7     7     7     7     7     7     7     7
     8     8     8     8     8     8     8     8     8     8     8
     9     9     9     9     9     9     9     9     9     9     9
    10    10    10    10    10    10    10    10    10    10    10
    11    11    11    11    11    11    11    11    11    11    11
>> 
>> cac
cac = 
    [4x11 double]    [7x11 double]    [5x11 double]
>> cac{1}
ans =
     1     1     1     1     1     1     1     1     1     1     1
     2     2     2     2     2     2     2     2     2     2     2
     3     3     3     3     3     3     3     3     3     3     3
     4     4     4     4     4     4     4     4     4     4     4

[Jessica Smith]

Thats exactly what I was hoping for, thank you Per