Plotting a function of determinant values vs n values.

Hi, so I have a function s(n), that spits out a n*n matrix. What I want to do is plot the determinant of each s(n) matrix that my s function makes and plot it against n from 1 to 32. I think I have to make a for loop, but I'm not entirely sure how to go about it.

Here's my code for the s function:

if true
  % code
function[output]=s(n)
output=zeros(n);
for i = 1:n
  for j=1:n
      output(i,j)=sqrt(2./n)*sin((pi*(i-.5)*(j-.5))./n);
  end
end
end

end

Answer 1

[KSSV]

          I didn't get your question exactly. I understand the following:
      You want to display the output of the above function s.

      For a given n the above function gives output a matrix of size nXn. As it is a matrix, you can view it using surf, pcolor.

Eg.

    K   = s(100) ;
      surf(K) ; shading interp ;
      pcolor(K) ; shading interp ;

Answer 2

[Torsten]

for k=1:32 
  index(k) = k;
  output = s(k);
  determinant(k) = det(output);
end
plot(index,determinant)

Best wishes

Torsten.

Answer 3

[José-Luis]

I'm on a one liner spree, and you don't actually need those loops:

 myFun = @(x) det(bsxfun(@(ii,jj) sqrt(2./n)*sin((pi*(ii-.5)*(jj-.5))./n),1:x,(1:x)'));

 fplot(myFun,[1 32])