How can I create a function that returns a function?

I'm tryng to create a function that returns to me the interpolation polynom of newton. This is the code:
function Y=newton(x,y)
syms X;
n=length(x);
b=zeros(n,n);
b(:,1)=y(:);
%finite difference matrix
for j=2:n
for i=1:n-j+1
b(i,j)= (b(i+1,j-1)-b(i,j-1))/(x(i+j-1)-x(i));
end
end
%interpolation polynom
yint=b(1,1);
xt=1;
for j=1:n-1
xt=xt*(X-x(j));
yint=yint+b(1,j+1)*xt;
end
Y=yint
It's already working, but I want the output to be a function, so I can calculate it's value in any point, make graphics, etc.

2 commentaires

Vitor Pessoa
Vitor Pessoa le 14 Août 2016
Modifié(e) : Geoff Hayes le 14 Août 2016
function Y=newton(x,y)
syms X;
n=length(x);
b=zeros(n,n);
b(:,1)=y(:);
%finite difference matrix
for j=2:n
for i=1:n-j+1
b(i,j)= (b(i+1,j-1)-b(i,j-1))/(x(i+j-1)-x(i));
end
end
%interpolation polynom
yint=b(1,1);
xt=1;
for j=1:n-1
xt=xt*(X-x(j));
yint=yint+b(1,j+1)*xt;
end
Y=yint
Sorry, it was supposed to come out like this.
Vitor - to properly format your code, highlight that text which is code and press the {}Code button.

Connectez-vous pour commenter.

Réponses (1)

Walter Roberson
Walter Roberson le 14 Août 2016

0 votes

Functions cannot return functions. Functions can return function handles, and functions can return symbolic expressions, and functions can return symbolic functions. The Y that you compute is already a symbolic expression; if you want to turn it into a function handle, use matlabFunction

Catégories

En savoir plus sur Programming dans Centre d'aide et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by