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How to Write all of an if-statement in a Single Lline?

726 vues (au cours des 30 derniers jours)
Rightia Rollmann
Rightia Rollmann le 16 Août 2016
Modifié(e) : Angelo Yeo le 8 Juil 2023
Is there any way to write all of an if-statement in a single line?
if A == 1 B = 2 elseif B = 3 end

Réponse acceptée

Azzi Abdelmalek
Azzi Abdelmalek le 16 Août 2016
Modifié(e) : Azzi Abdelmalek le 16 Août 2016
if A ==1 B = 2, else B = 3, end
But what is the aim of this?
  5 commentaires
Steven Lord
Steven Lord le 13 Avr 2021
Consider writing a "logme" function.
function logme(messageToLog)
verbose = true;
if verbose
fprintf('%s', messageToLog)
end
end
Now your code will contain calls to logme.
logme("Diagnostic message #1")
If you want to run without displaying these messages, change the definition of verbose inside logme. You could potentially also modify logme to log those messages not to the screen but to a log file without changing the callers of logme.
Angelo Yeo
Angelo Yeo le 8 Juil 2023
Modifié(e) : Angelo Yeo le 8 Juil 2023
If you want to set up if-else statement with a single line and make it into an inline funciton, you can think of such a thing.
ternary = @(varargin) varargin{end - varargin{1}};
ternary(true,'yes','no') % If the first argument is true, the result becomes 'yes'
ans = 'yes'
ternary(false,'yes','no') % If the first argument is false, the result becomes 'no'
ans = 'no'

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Plus de réponses (1)

KarlHoff
KarlHoff le 20 Oct 2021
You can employ logicals as factors toggling between 0 and 1:
B = 2 + 1*(A~=1);
%or
%B = 3 + (-1)*(A==1) ; % just roles reversed - depending on taste
This approach works whenever your if-statement just discriminates between two versions of a single assignment to one and the same variable as your example does.
I personally find this particular useful if there is a base value (here 2) and some delta added conditionally (here, +1 to obtain 3). You can also extend for further conditions.
  2 commentaires
Reno Filla
Reno Filla le 9 Déc 2021
The problem is if you want to get NaN on the case of, for example A==1
2+NaN*(A==1) doesnt work because 0*NaN return NaN just as 1*NaN does.
Also employing the NaN() function like
2+NaN(A==1) doesnt help since NaN(0) returns [] and canot be added to a scalar.
Any ideas?
KarlHoff
KarlHoff le 10 Déc 2021
How about
0/(A-1) + 3 %returns different numeric values for different A ~= 1
or
0/( (A==1)-1 ) + 3 % returns 3 for all A ~= 1

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