How do i call a function inside another function?

265 vues (au cours des 30 derniers jours)
Mohammed
Mohammed le 3 Sep 2016
Commenté : Jan le 18 Déc 2018
i wrote 2 functions separately. in one of these functions, i need to call the other function inside it? how do i do that? Thanks :)

Réponses (2)

KSSV
KSSV le 3 Sep 2016
I am giving an example here. The below first function calls a seconds function to calculate the sum of three numbers.
function K = firstfunction(a,b,c)
L = secondfunction(b,c) ;
K = a+L ;
This is the second function which calculates sum of two numbers.
function L = secondfunction(b,c)
L = b+c ;
Call the first function in Main file/ matlab work space:
s = firstfunction(1,2,3) ;
  3 commentaires
Stephen23
Stephen23 le 18 Déc 2018
Modifié(e) : Stephen23 le 18 Déc 2018
"My question is will the variable L be local or global to the calling function?"
L is not declared as global. It exists
  1. in the workspace where it is defined, and
  2. where it is passed as an output argument.
What do you mean by "the calling function" ?
Jan
Jan le 18 Déc 2018
@Soumen Kuma Mondal: Try it. It is very cheap to run the shown code and to use the debugger to step throught the code line by line. Then you can see in the WorkspaceBrowser, which variables are existing.
You need the command global to make a variable global. Another method to share data is to created a nested function:
function K = firstfunction(a,b,c)
L = secondfunction(b,c) ;
K = a+L ;
function L = secondfunction(b,c)
L = b+c ;
disp(K)
end
end
Now secondFunction is visible inside the firstFunction only and e.g. K is existing inside secondFunction.

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KSSV
KSSV le 3 Sep 2016
simple....write the function (output = functionname(inputs)) inside the function you want...
  1 commentaire
Mohammed
Mohammed le 3 Sep 2016
Thank you! i tried that but it does not work:( so i wrote the main function and then i called the other function inside it(in the same format you have specified). i think this is because the inputs of the function i called are not specified so MATLAB will not be able to run the code while it contains other unknowns from the previous function so i think i would have to enter the inputs of the other function i called but i do not know how to do that!

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