Suppose we have an array r=(2,2,2) filled with zeros and ones. How to count up how many zeros and how many ones do we have?

 Réponse acceptée

Image Analyst
Image Analyst le 22 Sep 2016
Try this:
numOnes = sum(r(:))
numZeros = numel(r) - numOnes

4 commentaires

Vadim Tambovtsev
Vadim Tambovtsev le 22 Sep 2016
No, my array in more complicated. Array (m,n,k), contans "a" and "b" values. How many "a" and "b" are there?
Image Analyst
Image Analyst le 22 Sep 2016
Modifié(e) : Image Analyst le 22 Sep 2016
You could have sped this along by two hours by saying that first instead of saying the array is "filled with zeros and ones". So to count the number of a's and b's:
numA = length(find(r==a));
numB = length(find(r==b));
There are other ways, but this is fairly simple and compact.
Vadim Tambovtsev
Vadim Tambovtsev le 22 Sep 2016
Modifié(e) : Image Analyst le 22 Sep 2016
quality control:
dd=[ 3 7; 4 5]
num7=sum(find(dd==7))
output:
num7= 3
Why is it 3? isn't it supposed to be 1, because there is 1 "7" in the array?
Image Analyst
Image Analyst le 22 Sep 2016
Use length() instead of sum().

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