Effacer les filtres
Effacer les filtres

Vectors must be the same length, Table

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Amritpal Kaur
Amritpal Kaur le 25 Sep 2016
Modifié(e) : Image Analyst le 25 Sep 2016
Hello,
So I have some uneven data tables like this:
And whenever I try to plot something like this:
plot(BackPocket.Ax, Ear.Ax)
I get the following error:
Vectors must be the same length.
How can I get past this by truncating, removing etc. non-matching rows?
Thanks.

Réponse acceptée

Image Analyst
Image Analyst le 25 Sep 2016
How can you plot Ear vs. BackPocket if they don't have the same number of elements? Do you want to plot each separately versus their index? If so
plot(BackPocket.Ax, 'b*-');
hold on;
plot(Ear.Ax, 'rd-');
  2 commentaires
Amritpal Kaur
Amritpal Kaur le 25 Sep 2016
No I just want to truncate the one table that has more data to match the one that has less. Any easy way to do this?
Image Analyst
Image Analyst le 25 Sep 2016
Modifié(e) : Image Analyst le 25 Sep 2016
Find the number of rows and plot the min
rows = min([length(BackPocket.Ax), length(Ears.Ax)]);
plot(BackPocket(1:rows).Ax, plot(Ear(1:rows).Ax, 'b*-');
Or maybe it's
plot(BackPocket{1:rows}.Ax, plot(Ear{1:rows}.Ax, 'b*-');
Or maybe it's
plot(BackPocket.Ax(1:rows), plot(Ear.Ax(1:rows), 'b*-');
-- not sure without trying it.

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