Hi all,
I'd like to get all combinations for all elements in a cell structure. For example,
var = rand(20, 3);
no = 5;
numcell = mat2cell(var, size(var, 1)/no*ones(1, no), ones(1, 3));
result in a 5 by 3 cell 'numcell' which contains 4 by 1 double for each cell.
I'd like to find all combinations among 5 by 3 'numcell', performing the calculation numcell{:}*numcell{:}' for each cell element of numcell. So that I'll get all permutation and combination of numcell{i}'*numcell{j}.
Thanks!

 Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 26 Sep 2016
Modifié(e) : Andrei Bobrov le 26 Sep 2016
I correctly understand:
out = cellfun(@(x)a(:).'*a(:),numcell);

5 commentaires

Xiaohan Du
Xiaohan Du le 26 Sep 2016
Hi Andrei,
Sorry for my explanation, the 'out' is not what I wanted. I meant all permutation and combinations of cells in numcell.
I've corrected my question, please see it.
Andrei Bobrov
Andrei Bobrov le 26 Sep 2016
Modifié(e) : Andrei Bobrov le 26 Sep 2016
Maybe as?
a = cat(2,numcell{:});
M = a.'*a;
Xiaohan Du
Xiaohan Du le 26 Sep 2016
I think this is it! Thanks a lot!
Stephen23
Stephen23 le 26 Sep 2016
Modifié(e) : Stephen23 le 26 Sep 2016
@Xiaohan Du: so what is the point in converting the data to a cell array, when the first step when performing this calculation is to get all the numeric arrays out of the cell array and concatenate them together?
Why bother with the cell array at all, when you don't use it for anything?
I am agree with Stephen, just:
a = reshape(var,4,:);
M = a.'*a;

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