values in file names

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franco otaola
franco otaola on 10 Oct 2016
Commented: franco otaola on 10 Oct 2016
hello everybody i am trying to use the name of the files (that are numbers) 09.xls,08.xls....etc. to create a matrix with them so i can relate them with the values they have inside.
d=dir('*.xls')
Name=ones(1,length(d));
for i=1:length(d)
[path,name,ext]=fileparts(d(i).name);
B=Name*name
...
end
my problem is that when i try to use name (as an escalar)to have the value it use '09' for exaple. then i try to make the matrix with all the values together(B) so, each value is stocked inside the matrix as the loop advance, matlab gives me things that doent have any sense (or at least for me...). eg. i have 9 excels, 02,03,04,05,06,07,08,09,10.xls so each time name would give 02,03,04,05,06,07,08,09 and 10 and the matrix Name would be [1;1;1;1;1;1;1;1;1] (a matrix of 9x1) when i try to calculate B (as in the code B=Name*name), matlab gives me B=[48,49;48,49;48,49;48,49;48,49;48,49;48,49;48,49;48,49] (a matrix of 9x2) i typed in the command window Name and name and it gives me the values i attend
>> name
name =
10
>> Name
Name =
1
1
1
1
1
1
1
1
1
>> Name*name
ans =
49 48
49 48
49 48
49 48
49 48
49 48
49 48
49 48
49 48
  1 Comment
franco otaola
franco otaola on 10 Oct 2016
i solved by adding str2num(name) i dont know what it was doing before....

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Accepted Answer

KSSV
KSSV on 10 Oct 2016
d=dir('*.xls')
Name=ones(1,length(d));
for i=1:length(d)
[path,name,ext]=fileparts(d(i).name);
B=Name*name ;
end
In the above Name is number and class double, where as name is string and class char. You cannot multiply two different classes. You have to convert name to number using str2num(). That's why it worked after converting.
You can check the classes of variables using class().
  1 Comment
franco otaola
franco otaola on 10 Oct 2016
Thanks!!!!! the getting started needs to add more things :p

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