Smooth a grid horizontally using interp2

I have a grid - bRMS - of Sound Speed values. The x dimension is distance, sampled in km every 0.00625 km.

vbx=[0.00625:0.00625:35]';

The y dimension is depth (in time), sampled every 0.001 s.

vby=[0:0.001:0.5]';

I would like to smooth the grid in the horizontal direction only, apply a conversion, then smooth in the vertical direction.

My code to smooth the grid horizontally is:

vbx_smooth=[0.00625:0.00625*100:35]';

[Xq,Yq]=meshgrid(vbx_smooth,vby);

Vq=interp2(vX,vY,bRMS,Xq,Yq);

This is producing an error

Error using griddedInterpolant

The grid vectors do not define a grid of points that match the given values.

Error in interp2>makegriddedinterp (line 228)
    F = griddedInterpolant(varargin{:});

Error in interp2 (line 136)
        F = makegriddedinterp(X, Y, V, method,extrap);

Any help with this problem would be appreciated.

[KSSV]

Check the dimensions of input's to interp2...they are not of same dimension, that's why error throwing out..

Answer 1

[Guillaume]

Did you make a mistake in the names of the input to interp2. I would have thought the correct call would be:

Vq = interp2(vbx, vby, bRMS, Xq, Yq);

If not, you need to explain what vX and vY are as they clearly are not what interp2 expects.

[K G]

Hi, yes I did, sorry. I have sorted that issue by using the correct inputs. Thank you for the help