Effacer les filtres
Effacer les filtres

How can I compare strings and create a new column with the comparison result?

2 vues (au cours des 30 derniers jours)
I have "cat1" and "cat2" that are 2 columns with strings:
If cat1 is low and cat2 is low, I want cat3 to be '1'; If cat1 is medium low and cat2 is medium low, I want cat3 to be '2'; And so on until high and high. If none of these conditions are satisfied, I want cat3 to be '0';
How can I do this? I tried this way but it says "Undefined operator '==' for input arguments of type 'cell'" :
teste1 = repmat( {''}, length(catpreco(:,1)), 1);
mask = catpreco(:,1) == 'low' & catconsumo(:,1)== 'low';
catpreco(mask) = cellfun(@(S) [S, '1'], catpreco(mask), 'Uniform', 0);
mask = catpreco(:,1) == 'medium low' & catconsumo(:,1)== 'medium low';
catpreco(mask) = cellfun(@(S) [S, '2'], catpreco(mask), 'Uniform', 0);
mask = catpreco(:,1) == 'medium' & catconsumo(:,1)== 'medium';
catpreco(mask) = cellfun(@(S) [S, '3'], catpreco(mask), 'Uniform', 0);
mask = catpreco(:,1) == 'medium high' & catconsumo(:,1)== 'medium high';
catpreco(mask) = cellfun(@(S) [S, '4'], catpreco(mask), 'Uniform', 0);
mask = catpreco(:,1) == 'high' & catconsumo(:,1)== 'high';
catpreco(mask) = cellfun(@(S) [S, '5'], catpreco(mask), 'Uniform', 0);
  1 commentaire
Jan
Jan le 25 Oct 2016
I've formatted the code. Please use the "{} code" button to provide readable code. Thanks.

Connectez-vous pour commenter.

Réponse acceptée

Jan
Jan le 25 Oct 2016
Modifié(e) : Jan le 25 Oct 2016
The error message means, that you cannot compare a cell array with a string using the == operator. Use strcmp instead:
cat3 = cell(size(cat1));
cat3(:) = {'0'};
mask = strcmp(cat1, 'low') & strcmp(cat2, 'low');
cat3(mask) = {'1'};
mask = strcmp(cat1, 'medium low') & strcmp(cat2, 'medium low');
cat3(mask) = {'2'};
mask = strcmp(cat1, 'medium') & strcmp(cat2, 'medium');
cat3(mask) = {'3'};
mask = strcmp(cat1, 'medium high') & strcmp(cat2, 'medium high');
cat3(mask) = {'4'};
mask = strcmp(cat1, 'high') & strcmp(cat2, 'high');
cat3(mask) = {'5'};
A loop might be nicer:
list = {'low', 'medium low', 'medium', 'medium high', 'high'};
for k = 1:5
mask = strcmp(cat1, list{k}) & strcmp(cat2, list{k}));
cat3(mask) = {sprintf('%d', k)};
end
  2 commentaires
Guillaume
Guillaume le 25 Oct 2016
Even simpler (no loop):
list = {'low', 'medium low', 'medium', 'medium high', 'high'};
cat3 = zeros(size(cat1));
[~, cat1result] = ismember(cat1, list);
[~, cat2result] = ismember(cat2, list);
cat3(cat1result == cat2result) = cat1result(cat1result == cat2result);
Eduardo Rocha
Eduardo Rocha le 25 Oct 2016
Thank you, now its easier to understand and the code works perfectly :)

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Characters and Strings dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by