Secant method error, "subscript indicies must be real or positive integers"

12 vues (au cours des 30 derniers jours)
Harjot Purewal
Harjot Purewal le 31 Oct 2016
Commenté : Harjot Purewal le 31 Oct 2016
here is my code, I get the error at line 10 at x(n+1) = x(n) - .... I have also attached it as an .m file
Matlab code
y = @(x) x.^3 - .3;
x(1) = .01;
x(2) = .02;
tol = 1e-5;
eps = 500;
iteration_secant = 0;
n = 1;
while abs(eps) > tol
x(n+1) = x(n) - ((y(x(n))*(x(n)-x(n-1))/(y(x(n))-y(x(n-1)))));
iteration_secant = iteration_secant +1;
eps = ((x(n+1) - x(n))/x(n));
n=n+1;
if n > 100
break
end
end
x(n+1)

Réponses (1)

Roger Stafford
Roger Stafford le 31 Oct 2016
You enter the while loop with n = 1. This means that x(n-1) would have an index value of zero. This is a no-no in Matlab. You will have to revise your code to avoid this.
  1 commentaire
Harjot Purewal
Harjot Purewal le 31 Oct 2016
I have changed it to n=2; from n=1; however I still get the same error and for some reason the value of n is still 1 when I run my code any idea of why this is the case?

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