how to get the specific member data from a struct array?

6 vues (au cours des 30 derniers jours)
xiao
xiao le 4 Nov 2016
for example,
b=struct('name','JPEG','age','18') ;
c=repmat(b,3,1) ;
d=c.name;
c.name
why is the result of "c.name" different from the result of "d=c.name"?
how to get the member data directly from a struct array or matrix? such as c.name?
and another question, how to create a struct array or matrix directly just like zeros(2,3), but struct(2,3) doesn't work, so how?

Réponse acceptée

George
George le 4 Nov 2016
From the doc on struct
"When you access a field of a nonscalar structure, such as s.f, MATLAB® returns a comma-separated list. In this case, s.f is equivalent to s(1).f, s(2).f, s(3).f."
So your d = c.name is equivalent to
d = c(1).name, c(2).name, c(3).name.
Try
[d,e,f] = c.name
to see the difference. See here for more info on how to access data in a struct.
struct(2,3) doesn't work because it's trying to create a 1x1 struct array with field:2 and value:3. Field needs to be a char array.
  1 commentaire
xiao
xiao le 5 Nov 2016
thank you! inspired by you, i try d = [c(1).name, c(2).name, c(3).name] and
d=[c.name] for a large struct to put the result together, but need to redivide
the result array. so maybe for loop is required.
and to create a struct matrix, maybe the for loop method or repmat way is needed.

Connectez-vous pour commenter.

Plus de réponses (1)

Alexandra Harkai
Alexandra Harkai le 4 Nov 2016
Modifié(e) : Alexandra Harkai le 4 Nov 2016
What c is is what is called a nonscalar struct array. Then "You cannot assign the list to a single variable with the syntax v = s.f because the fields can contain different types of data." as per the Documentation, so variable d gets only c(1).name, and hence they will be different.
  2 commentaires
xiao
xiao le 5 Nov 2016
Modifié(e) : xiao le 5 Nov 2016
thx! so, for loop method is required to get the data of a struct array or matrix?
Alexandra Harkai
Alexandra Harkai le 7 Nov 2016
Please do not change your question once it has been answered, it is preferred to start new one.

Connectez-vous pour commenter.

Catégories

En savoir plus sur Structures dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by